One year age, Promila was four times as old as her daughter Jenilia. Six years hence, Promila?s age will exceed her daughter’s age by 9 years. The ratio of the present ages of Promila and her daughter is :
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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
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The sum of the present ages of a father and his son is 60 years. Six year ago, father’s age was five times the age fo the son. After 6 years, son’s age will be
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5 years ago, sister’s age was 5 times the age of her brother and the sum of present ages of sister and brother is 34 years. What will be the age of her brother after 6 years?
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Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is :
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The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Top 20 Aptitude Question on Problems on Ages
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